A hiking club has 9 members. How many ways can they choose a president, vice president, secretary, and treasurer from among the members?

the\ variation\ without\ repetition:\\\\P(n;k)= \frac{\big{n!}}{\big{(n-k)!}} \\\\---------------------\\\
=9\ \ \ and\ \ \ k=5\\\\\Rightarrow\ \ \ P(9;5)=\frac{\big{9!}}{\big{5!}}=\frac{\big{5!\cdot6\cdot7\cdot8\cdot9}}{\big{5!}}=3024\\\\Ans.\ there\ are\ 3024\ ways\ to\ choose.

Answered by kate200468 | 2024-06-10

3024 ;

Answered by 69g1izzy6993 | 2024-06-16

There are 3024 ways to choose a president, vice president, secretary, and treasurer from 9 members of a hiking club. This is calculated using permutation principles by choosing each position one after another. The steps involve multiplying the choices available at each stage of selection.
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Answered by kate200468 | 2024-12-23