X+2y=14, okay so you have to write X+2(3x-14)=14
{ y = 3 x − 14 x + 2 y = 14 S u b s t i t u t i o n x + 2 ( 3 x − 14 ) = 14 x + 6 x − 28 = 14 7 x − 28 = 14 ∣ a dd 28 7 x = 42 ∣ d i v i d e b y 7 x = 6 y = 3 x − 14 = 3 ∗ 6 − 14 = 18 − 14 = 4 S o l u t i o n : { x = 6 y = 4
We solved the system of equations by substituting one equation into the other. This resulted in x = 6 and y = 4 . Therefore, the solution to the system is { x = 6 , y = 4 } .
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