How do I solve this equation?

\[ 8(c-9) = 6(2c-12) - 4c \]

8(c-9) = 6(2c-12)-4c
Okay let us solve it together. Multiply out and expand the brackets.
8 c -8 9 = 6 2c -6 12 -4c 8c -72 = 12c -72 -4c Re arrange by taking the cs to one side 8c -12c +4c = -72 + 72 0 = 0
For this kind of statement it means C can be any number, and it would satisfy the equation. Cheers.

Answered by olemakpadu | 2024-06-10

The solution to the equation 8(c-9) = 6(2c-12) - 4c is c can be any real number.
Here, we have,
To solve the equation 8(c-9) = 6(2c-12) - 4c, we can follow these steps:
Step 1: Simplify both sides of the equation by performing the multiplication.
On the left side, distribute the 8 to both terms inside the parentheses:
8(c-9) = 8c - 72
On the right side, distribute the 6 to both terms inside the parentheses:
6(2c-12) = 12c - 72
The equation now becomes:
8c - 72 = 12c - 72 - 4c
Step 2: Simplify further by combining like terms.
On the right side, simplify 12c - 4c to 8c:
8c - 72 = 8c - 72
Step 3: Bring the** variables **to one side and the constant terms to the other side.
Subtract 8c from both sides:
8c - 8c - 72 = 8c - 8c - 72
Simplifying the equation:
-72 = -72
Step 4: Analyze the equation.
The equation -72 = -72 is true.
This means that the **equation **is an identity, and any value of c will satisfy the equation.
Therefore, the solution to the equation 8(c-9) = 6(2c-12) - 4c is c can be any real number.
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Answered by duttakoushik094 | 2024-06-18

To solve the equation 8 ( c − 9 ) = 6 ( 2 c − 12 ) − 4 c , we first distribute and simplify both sides, arriving at the statement 0 = 0 . This means the equation holds true for all values of c , indicating there are infinitely many solutions. Therefore, c can be any real number.
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Answered by olemakpadu | 2024-09-30