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In Mathematics / Middle School | 2014-10-23

To find the product \(\frac{3}{7} \times \frac{4}{9}\), Cameron simplified \(\frac{3}{7}\) to \(\frac{1}{7}\) and then multiplied the fractions \(\frac{1}{7}\) and \(\frac{4}{9}\) to find the product \(\frac{4}{63}\).

What is Cameron's error?

Asked by msajireh

Answer (2)

he should not have simplified 3/7 to 1/7 as they do not equal - he now has 2 less sevenths than before.

Answered by anniedavies96 | 2024-06-10

Cameron incorrectly simplified 7 3 ​ to 7 1 ​ , which is not correct. The right approach is to multiply the fractions directly without simplifying incorrectly, leading to the product 21 4 ​ .
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Answered by anniedavies96 | 2024-12-26

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