x − 3 ( x − 1 ) + 8 ( x − 3 ) = 6 x + 7 − 5 x x − 3 x + 3 + 8 x − 24 = 6 x + 7 − 5 x ∣ g ro u p in g s imi l a r f a c t ors 6 x − 21 = − x + 7 ∣ a dd x 7 x − 21 = 7 ∣ a dd 21 7 x = 28 ∣ d i v i d e b y 7 x = 4 S o l u t i o n i s x = 4.
The solution to the equation is x = 7 . This was determined by distributing, simplifying, and isolating x through algebraic manipulation. Finally, the solution was verified by substituting it back into the original equation.
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