H2GM - Every Question Matters. Logo

In Mathematics / Middle School | 2014-10-22

A water tank holds 24,000 gallons. How many hours will it take for 2/3 of the water to be used if the water is used at an average rate of 650 gallons per day?

Asked by Andreita

Answer (3)

590.76 hours ;

Answered by wifilethbridge | 2024-06-12

The water tank holds 24,000 gallons.
To find out how many hours it will take for 2/3 of the water to be used:
Calculate the total amount of water to be used: 24,000 gallons * 2/3 = 16,000 gallons.
Divide the total amount of water to be used by the average daily rate of water usage: 16,000 gallons รท 650 gallons/day = 24.62 days.
Therefore, it will take approximately 24.62 days or 24.62 * 24 hours = 591.71 hours to use 2/3 of the water in the tank.

Answered by LivUllmann | 2024-06-24

It will take approximately 590.76 hours to use 2/3 of the water in a 24,000-gallon tank at a rate of 650 gallons per day. This was calculated by determining that 16,000 gallons need to be used, which takes about 24.615 days, equivalent to 590.76 hours. This process involved basic division and multiplication to convert between gallons, days, and hours.
;

Answered by wifilethbridge | 2024-12-17