y + 7 = 2 1 ( x + 2 ) ∣ m u lt i pl y b o t h s i d es b y 2 2 y + 14 = x + 2 ∣ s u b t r a c t x an d 2 f ro m b o t h s i d es − x + 2 y + 14 − 2 = 0 − x + 2 y + 12 = 0 ∣ c han g e s i g n s x − 2 y − 12 = 0
The equation y + 7 = 2 1 ( x + 2 ) can be rearranged into standard form as x − 2 y = 12 by eliminating the fraction and rearranging the terms. This involves multiplying through to remove fractions and isolating x on one side. Ultimately, the final answer is in the form A x + B y = C where A = 1 , B = − 2 , and C = 12 .
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