A student drops a ball from a window 3.5 meters above the sidewalk. How fast is the ball moving when it hits the ground?
Answer (3)
to answer this you must know that the acceleration caused by gravity upon the ball, or any object, is -9.8 m/s^2 there's two ways to solve this first, use the position equation x=(1/2)at^2+Vot+Xo Xo, the initial position, is 3.5 m x(t), the final position, is 0 m (the ground) Vo, the initial velocity, is 0 m/s, since you just drop the ball and a is -9.8 so 0=(1/2)(-9.8)t^2+3.5 -3.5=-4.9t^2 t^2=0.71 t=0.845 so it takes the ball 0.845 s to hit the ground now, using the velocity equation, v=at+Vo, v=(-9.8)(0.845)+0=-8.28 m/s therefore, the speed of the ball is 8.28 m/s when it hits the ground
The ball will be moving at a **speed **of approximately 8.23 m/s when it hits the ground. ;
The speed of the ball when it hits the ground after being dropped from 3.5 meters is approximately 8.28 m/s. This calculation uses the acceleration due to gravity, which is -9.8 m/s². The formula v 2 = v 0 2 + 2 ah helps us find the final velocity before impact.
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