A dragster in a race accelerated from rest to [tex]60 \, \text{m/s}[/tex] by the time it reached the finish line. The dragster moved in a straight line and traveled with an acceleration of [tex]8.0 \, \text{m/s}^2[/tex].

How long did it take the dragster to reach the finish line?

Dragster take 7.5 second .
According to first equation of motion ,
V = U + at
t = (V -U)/a
V= final velocity
U=initial velocity
a = acceleration
t = time
given that,
U = 0 m/s (object starts from rest)
V = 60 m/s
a= 8 m/s2
t =?
t = (60 m/s – 0 m/s)/8 m/s2
t = 7.5 s
Thus, we can conclude that, dragster take 7.5 second .
Learn more about** equations of motion** here:
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Answered by virtuematane | 2024-06-15

vf = final velocity vo = initial velocity a = acceleration t = time
use the following equation
vf = vo + at
since vo = 0 m/s (stopped), that term drops out and you're left with . . .
vf = at
(60 m/s) = (8.0 m/s²)t
t = (60 m/s)/(8.0 m/s²) = 7.5 seconds
t = 7.5 seconds

Answered by Anonymous | 2024-06-25

The dragster took 7.5 seconds to reach the finish line after accelerating from rest to 60 m/s with an acceleration of 8.0 m/s². This was calculated using the kinematic equation that relates final velocity, initial velocity, acceleration, and time. By rearranging the equation, we found that time equals the final velocity divided by acceleration.
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Answered by Anonymous | 2024-09-26