A box contains red and blue chips. There are 2 more blue chips than red chips. If the number of red chips is tripled and the number of blue chips is doubled, there will be an equal number of red and blue chips. How many blue chips does the original box contain?
Answer (2)
B = (R+2) 3R = 2B 3R = 2(R+2) 3R = 2R + 4 3R-2R = 4 R= 4 B = R + 2, so B = 6
The box originally contains 6 blue chips. This was determined by establishing equations based on the relationships between the numbers of red and blue chips and then solving for the variables. The number of red chips is 4, leading to 6 blue chips due to the stated conditions.
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