A candy store wants to create a mix of two hard candies. One is priced at $5.45 per pound, and the other is priced at $7.33 per pound. How many pounds of the $7.33 candy should be mixed with 11 pounds of the $5.45 candy to sell the mixture for $6.14 per pound?

1. Write an equation for the problem.
2. Solve the equation.
3. Explain the solution.

x − am o u n t o f c an d y w hi c h cos t 5 , 45$ y − am o u n t o f c an d y w hi c h cos t 7 , 33$ 7 , 33 ∗ y + 11 ∗ 5 , 45 = 6 , 14 ( 11 + y ) 7 , 33 y + 59 , 95 = 67 , 54 + 6 , 14 y ∣ s u b t r a c t 6 , 14 y 1 , 19 y = 67 , 54 − 59 , 95 1 , 19 y = 7 , 59 ∣ d i v i d e b y 1 , 19 y = 6 , 38 p o u n d 6 , 38 p o u n d s s h o u l d b e mi x e d w i t h t h ose w i c h cos t 5 , 45.

Answered by luana | 2024-06-10

The store needs to mix approximately 6.38 pounds of the $7.33 candy with 11 pounds of the $5.45 candy to sell the mixture at $6.14 per pound. This was determined by setting up an equation based on the total cost of the candies. Solving the equation revealed the necessary amount needed of the more expensive candy.
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Answered by luana | 2024-09-17