A shopper in a supermarket pushes a loaded cart with a horizontal force of 13.3 Newtons. The cart has a mass of 25.1 kg and is pushed for 3.60 seconds, starting from rest.

(a) How far (in meters) will the cart move during these 3.60 seconds? (Ignore friction.)

(b) How far (in meters) will the cart move in the 3.60-second interval if the shopper places her 27.4-N child in the cart before she begins to push it?

Applying Newton's Second Law of Motion, the cart moves 3.43 meters when it is pushed alone. However, after placing a 27.4-N child in the cart, it moves 1.65 meters due to the greater weight reducing acceleration. ;

Answered by MinkaKelly | 2024-06-18

By applying Newton's Second Law, we calculate the cart's acceleration and then use this to calculate the** distance **travelled in the given time. Without the child, the cart travels 3.43 meters in 3.60 seconds. With the child, the cart travels 1.64 meters in 3.60 seconds. ;

Answered by Qwshop | 2024-06-18

The cart moves approximately 3.43 meters when pushed alone and about 3.09 meters when a child is added to it, due to the increased mass reducing its acceleration.
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Answered by MinkaKelly | 2024-12-26