At a certain instant, an object is moving to the right with a speed of 1.0 m/s and has a constant acceleration to the left of 1.0 m/s². At what later time will the object momentarily be at rest?

For this problem, you would use the equation v=u+at. In this case, u=1 v=0 (when the object is at rest) a=-1 v=u+at 0=1+(-1)t t=1 second

Answered by matthewhamill | 2024-06-10

The later time in which the object will momentarily be at rest is determined as 1 second.
Time of motion of the object
The time of motion of the object is calcualted as follows;
v = u + at
where;

v is the final velocity of the object

when the object stops, the final velocity is zero
0 = u + at
0 = 1 + (-1)t
t = 1 s
Thus, the later time in which the object will momentarily be at rest is determined as 1 second.
Learn more about time of motion here: https://brainly.com/question/2364404

Answered by onyebuchinnaji | 2024-06-16

The object will be momentarily at rest after 1.0 second due to its constant leftward acceleration. We calculated this using the formula for velocity under constant acceleration. The initial rightward speed of 1.0 m/s and a leftward acceleration of 1.0 m/s² leads to this result after one second.
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Answered by onyebuchinnaji | 2024-09-03