The width of David's tent is 5 feet. The length is twice the width. David's rectangular air mattress measures 3 feet by 6 feet. If David puts the air mattress in the tent, how many square feet of floor space will be available for the rest of his things?
Answer (2)
A re a o f D a v i d ′ s t e n t : 5 ⋅ 2 ⋅ 5 = 50 f t 2 A re a o f ai r ma tt ress : 3 ⋅ 6 = 18 f t 2 50 − 18 = 32 f t 2 F or t h e res t t h ere i s a v ai l ab l e 32 f t 2 .
The area of David's tent is 50 square feet, and the area of the air mattress is 18 square feet. After placing the air mattress in the tent, there will be 32 square feet of available floor space. This is calculated by subtracting the mattress area from the tent area.
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