A re a o f c l ose t = 2 ∗ 2 + 2 l e n g t h 9 A re a o f c l ose t = A re a o f b e d roo m 9 A re a o f c l ose t = 90 ∣ d i v i d e b y 9 A re a o f c l ose t = 10 f ee t 2 10 = 2 ∗ 2 + 2 l e n g t h 10 = 4 + 2 l e n g t h ∣ s u b t r a c t 2 6 = 2 l e n g t h ∣ d i v i d e b y 2 l e n g t h = 3 f ee t
**Answer:**The length of closet is 5 ft. ;
The length of Jackson's closet is 5 feet. This is found by using the relationship between the areas of the bedroom and the closet. The area of the closet is determined by its width and length, leading to the solution.
;