A hiker hikes in a straight line and maintains a constant velocity of +0.5 m/s. At time [tex]t = 0.0 \, \text{s}[/tex], the hiker is 30 m from point A. What is the displacement from point A at [tex]120 \, \text{s}[/tex]?
Answer (2)
60 meters, because he starts at point A and moves with a constant velocity of 0.5 m/s for 120s, 0.5x120=60 so the displacement is 60 meters, because the displacement is the distance between the starting point and the finishing point.
The hiker's displacement from point A at 120 s is − 30 m , indicating that the hiker moved 30 meters in the opposite direction from point A. This displacement accounts for the initial position and the total distance traveled. The negative sign suggests movement in the opposite direction from point A.
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