How do you graph the equation \(2x + 8y = -32\)?

First, subtract 2x from both sides of the equation to get 8y = -2x - 32. Then, divide the equation by 8, to get y = -x/4 - 4. Your y-intercept will be -4, and it's slope will be -1/4.

Answered by andrewhong7 | 2024-06-10

To graph 2 x + 8 y = − 32 , first convert it to slope-intercept form y = − 4 1 ​ x − 4 . Plot the y-intercept at (0, -4) and use the slope − 4 1 ​ to find another point, then draw the line. This results in a clear representation of the equation on the graph.
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Answered by Anonymous | 2024-10-30