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In Mathematics / Middle School | 2014-10-15

Simone has 20 bills. One-fifth of the bills are hundreds, 1/4 of them are fifties, and 1/10 of them are $20s. The rest of the bills are tens.

Simone has $780 altogether. How many of each kind of bill does she have?

Asked by Zubairn

Answer (2)

If Simone has 20 bills, then:
1/5 of 20 = 4 [hundreds] 1/4 of 20 = 5 [fifites] 1/10 of 20 = 2 [$20s]
4 * 100 + 5 * 50 + 2 * 20 = 400 + 250 + 40 = 690 [out of $780] 4 + 5 + 2 = 11 [out of 20 bills]
So now we can easily find out she had 9 bills of tens - because 20 - 11 = 9 or because (780 - 690) ÷ 10 = 90 ÷ 10 = 9.

Answered by SlowZasob | 2024-06-24

Simone has 4 hundred-dollar bills, 5 fifty-dollar bills, 2 twenty-dollar bills, and 9 ten-dollar bills. The total value of these bills sums to $780 as stated in the problem. The calculations demonstrate that all bills account for the total number and their respective values correctly.
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Answered by SlowZasob | 2024-12-26

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