Andre has more money than Bob. If Andre gave Bob $20, they would have the same amount. However, if Bob gave Andre $22, Andre would then have twice as much as Bob. How much does each one actually have? Explain why.
Answer (2)
y\ \ and\\ x-20=y+20\ \ and\\ 2(y-22)=x+22\\\\ x=y+40\ \ and\\ 2y-44=x+22\\\\ 2y-44=y+40+22\\ 2y-44=y+62\ \ \ \ |Add\ 44\\ 2y=y+106\ \ \ |subtract\ y\\ y=106\\\\ Andre\ has \ 146\$\ and\ Bob\ has\ 106\$."> x − A n d r e ′ s m o n ey y − B o b ′ s m o n ey x > y an d x − 20 = y + 20 an d 2 ( y − 22 ) = x + 22 x = y + 40 an d 2 y − 44 = x + 22 2 y − 44 = y + 40 + 22 2 y − 44 = y + 62 ∣ A dd 44 2 y = y + 106 ∣ s u b t r a c t y y = 106 A n d re ha s 146$ an d B o b ha s 106$.
Andre has $146 and Bob has $106. When Andre gives Bob $20, they have the same amount. When Bob gives Andre $22, Andre has twice as much as Bob.
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