A boat is rowed at 8 km/hr directly across a river that flows at 6 km/hr. What is the resultant speed?
Answer (2)
The **Resultant Speed **of boat rowed at 8km/hr directly across a river that flows at 6km/hr is 10km/hr
Given the data in the question;
Velocity of boat; V m = 8 km / h r
Velocity of the flowing river; V r = 6 km / h r
Resultant Velocity; V = ?
Now, as illustrated in the diagram below, a right angled triangle is formed.
Now, to get the V , which is the resultant velocity or speed, we make use of the Pythagorean theorem:
c 2 = a 2 + b 2
In our case,
V 2 = V r 2 + V m 2
We find the square root of both sides
V = V r 2 + V m 2
Now, we substitute in our given values
V = \sqrt{(6km/hr)^2 + (8km/hr)^2}\\\\V = \sqrt{ (36km^2/hr^2) + ( 64 km^2/hr^2)\\
V = \sqrt{100 km^2/hr^2
V = 10 km / h r
Therefore, The **Resultant Speed **of boat rowed at 8km/hr directly across a river that flows at 6km/hr is 10km/hr
Learn more; https://brainly.com/question/11737468
The resultant speed of the boat rowed at 8 km/hr across a river flowing at 6 km/hr is 10 km/hr, calculated using the Pythagorean theorem. This considers the velocities of both the boat and the river current as perpendicular components. Thus, we find that V = 8 2 + 6 2 = 10 km/hr .
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