In reaching her destination, a backpacker walks with an average velocity of 1.22 m/s due west. This average velocity results because she hikes for 6.44 km with an average velocity of 2.53 m/s due west, turns around, and hikes with an average velocity of 0.445 m/s due east.
How far east did she walk?
Answer (3)
Wow! 2.95m/s is a mighty fast pace for a backpacker. Must have one of those Star Wars anti-gravity packs. Also, I would be curious as to why she passed her destination and then walked back. Anyway, it goes like this: Say the time walking east is 't', and the total time is 'T'. Then 5340 m + .511 t = 1.43 T (This assumes that velocity is positive in both directions) Two unknowns in one equation. But you also know that the time spent walking west is 5340m/ 2.95m/s = 1810 sec. and the total time T = 1810 +t Substitute this into the first equation, and you can solve for t = 3092 sec. Then T = 4902 sec. and distance walked east is .511t = 1580m.
To calculate how far east the** backpacker **walked, we first find the time spent walking west by dividing the westward distance by the westward velocity. ;
The backpacker walked approximately 2843 meters east after hiking 6440 meters west. By analyzing her average velocities and calculating the total displacement, we can determine the distance she traveled in both directions. Setting up the average velocity equations allows for solving for the distance east she walked.
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