An airplane cruises at 880 km/h relative to the air. It is flying from Denver, Colorado, due west to Reno, Nevada, a distance of 1200 km, and will then return. There is a steady 90 km/h wind blowing to the east. What is the difference in flight time between the two legs?

This should go in mathematics, but I'll answer anyway. When the airplane goes west, then the wind will be pushing back on it, so the speed of the plane will go down to 790 km/h. 1200/790 is how long it will take for it to get to Reno. When it comes back, it gets a speed boost from the wind. Its new speed will be 880+90=970 1200/970 is how long it will take for the plane to return. 1200/790 - 1200/970 is your answer. 1.52-1.24=0.28 0.28 hours

Answered by MichaelLiu | 2024-06-10

Δ t = 0.28 h o u rs ;

Answered by aristocles | 2024-06-12

The difference in flight time between the airplane's trip from Denver to Reno and back is approximately 0.28 hours, which is about 16.8 minutes. The airplane travels slower against the wind and faster with the wind. This results in a longer flight time to Reno and a shorter time returning to Denver.
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Answered by aristocles | 2024-09-03